2n^2+13n-56=0

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Solution for 2n^2+13n-56=0 equation:



2n^2+13n-56=0
a = 2; b = 13; c = -56;
Δ = b2-4ac
Δ = 132-4·2·(-56)
Δ = 617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{617}}{2*2}=\frac{-13-\sqrt{617}}{4} $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{617}}{2*2}=\frac{-13+\sqrt{617}}{4} $

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